[example: Divisibility Poset]
Let $P=\{1,2,3,4,6,12\}$ and define $a \le b$ to mean $a \mid b$. The relation is reflexive because $a=1\cdot a$, so $a\mid a$ for every $a\in P$. It is antisymmetric because if $a\mid b$ and $b\mid a$, then $b=ra$ and $a=sb$ for positive integers $r,s$, hence $a=sra$, so $sr=1$, and therefore $r=s=1$ and $a=b$. It is transitive because if $a\mid b$ and $b\mid c$, then $b=ra$ and $c=tb$ for positive integers $r,t$, so $c=t(ra)=(tr)a$, hence $a\mid c$.
The minimum element is $1$, since
\begin{align*}
1\mid 1,\ 1\mid 2,\ 1\mid 3,\ 1\mid 4,\ 1\mid 6,\ 1\mid 12.
\end{align*}
The maximum element is $12$, since
\begin{align*}
1\mid 12,\ 2\mid 12,\ 3\mid 12,\ 4\mid 12,\ 6\mid 12,\ 12\mid 12.
\end{align*}
The element $2$ lies below $4,6,12$ because $4=2\cdot 2$, $6=3\cdot 2$, and $12=6\cdot 2$. The elements $4$ and $6$ are incomparable: $4\nmid 6$ because $6/4$ is not an integer, and $6\nmid 4$ because $4/6$ is not an integer.
For the interval from $2$ to $12$, an element $z\in P$ belongs to $[2,12]$ exactly when $2\mid z$ and $z\mid 12$. Checking the six elements of $P$, the possibilities are $2,4,6,12$, while $1$ fails $2\mid 1$ and $3$ fails $2\mid 3$. Thus
\begin{align*}
[2,12]=\{2,4,6,12\}.
\end{align*}
This example turns divisibility calculations into order-theoretic data: extrema, comparable pairs, incomparable pairs, and intervals are all read from the same relation $a\mid b$.
[/example]