Then $\operatorname{End}_{\mathcal{C}}(X)$ is closed under categorical composition: if $f,g \in \operatorname{End}_{\mathcal{C}}(X)$, then $f \circ g \in \operatorname{End}_{\mathcal{C}}(X)$. Moreover, $\operatorname{End}_{\mathcal{C}}(X)$ is a monoid under composition, with identity element $\operatorname{id}_X$. Equivalently, for all $f,g,h \in \operatorname{End}_{\mathcal{C}}(X)$,
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\begin{align*}
(f \circ g) \circ h = f \circ (g \circ h),
\end{align*}
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and for every $f \in \operatorname{End}_{\mathcal{C}}(X)$,
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\begin{align*}
\operatorname{id}_X \circ f = f = f \circ \operatorname{id}_X.
\end{align*}