[example: Three Prototype Meanings]
Let $u$ be a scalar field. For a steady field $u:\mathbb R^n\to\mathbb R$, the equation $\Delta u=0$ means
\begin{align*}
\partial_{x_1x_1}u(x)+\partial_{x_2x_2}u(x)+\cdots+\partial_{x_nx_n}u(x)=0
\end{align*}
at each point $x$, so the second-order bending in the coordinate directions balances to zero. For a time-dependent field $u:\mathbb R^n\times(0,\infty)\to\mathbb R$, the [heat equation](/page/Heat%20Equation) $\partial_tu-\Delta u=0$ is the same as
\begin{align*}
\partial_tu(x,t)=\Delta u(x,t),
\end{align*}
so the time change is determined by the spatial curvature.
For constant transport, fix $b=(b_1,\dots,b_n)\in\mathbb R^n$ and let $u_0\in C^1(\mathbb R^n)$. Define $u(x,t)=u_0(x-bt)$, where $x-bt=(x_1-b_1t,\dots,x_n-b_nt)$. By the chain rule,
\begin{align*}
\partial_tu(x,t)=\sum_{i=1}^n \partial_{x_i}u_0(x-bt)(-b_i)=-\sum_{i=1}^n b_i\partial_{x_i}u_0(x-bt).
\end{align*}
For each $j\in\{1,\dots,n\}$, the chain rule also gives
\begin{align*}
\partial_{x_j}u(x,t)=\sum_{i=1}^n \partial_{x_i}u_0(x-bt)\delta_{ij}=\partial_{x_j}u_0(x-bt).
\end{align*}
Hence
\begin{align*}
b\cdot\nabla u(x,t)=\sum_{i=1}^n b_i\partial_{x_i}u(x,t)=\sum_{i=1}^n b_i\partial_{x_i}u_0(x-bt).
\end{align*}
Combining the two displayed identities,
\begin{align*}
\partial_tu(x,t)+b\cdot\nabla u(x,t)=-\sum_{i=1}^n b_i\partial_{x_i}u_0(x-bt)+\sum_{i=1}^n b_i\partial_{x_i}u_0(x-bt)=0.
\end{align*}
Thus $\Delta u=0$ models balance, $\partial_tu-\Delta u=0$ models diffusion driven by curvature, and $\partial_tu+b\cdot\nabla u=0$ models rigid transport of the initial profile along the lines $x-bt=\text{constant}$.
[/example]