[example: Familiar Product Metrics on $\mathbb R^2$]
Take $X=Y=\mathbb R$ with the usual metric $d(s,t)=|s-t|$, and let $a=(0,0)$ and $b=(3,4)$. The coordinate distances are
\begin{align*}
d(0,3)=|0-3|=|-3|=3.
\end{align*}
and
\begin{align*}
d(0,4)=|0-4|=|-4|=4.
\end{align*}
For the taxicab product metric,
\begin{align*}
d_1(a,b)=d(0,3)+d(0,4)=3+4=7.
\end{align*}
For the Euclidean product metric,
\begin{align*}
d_2(a,b)=\bigl(d(0,3)^2+d(0,4)^2\bigr)^{1/2}=(3^2+4^2)^{1/2}.
\end{align*}
Since $3^2=9$ and $4^2=16$, this becomes
\begin{align*}
d_2(a,b)=(9+16)^{1/2}=25^{1/2}=5.
\end{align*}
For the supremum product metric,
\begin{align*}
d_\infty(a,b)=\max\{d(0,3),d(0,4)\}=\max\{3,4\}=4.
\end{align*}
Thus the same pair of points has distances $7$, $5$, and $4$ under $d_1$, $d_2$, and $d_\infty$, respectively. Both coordinate distances are nonzero, so all three metrics detect motion in both coordinates; by *[Product Metrics Induce the Product Topology](/theorems/8622)*, all three generate the usual topology on $\mathbb R^2$.
[/example]