[step:Transfer the identification back to Besov spaces via the retract pair $(P, S)$]
By the retract principle invoked in the third step,
\begin{align*}
(B^{s_0}_{p,q_0}, B^{s_1}_{p,q_1})_{\theta, q} = S\bigl((\ell^{q_0}_{s_0}(L^p), \ell^{q_1}_{s_1}(L^p))_{\theta, q}\bigr) \cap \mathcal{S}'(\mathbb{R}^n)
\end{align*}
with equivalent norms (the retract maps on both sides are the same $(P, S)$ from the second step). By the previous step, the right-hand side equals $S(\ell^q_{s_\theta}(L^p)) \cap \mathcal{S}'(\mathbb{R}^n)$, which by the construction of $S$ is exactly $B^{s_\theta}_{p, q}(\mathbb{R}^n)$ (with norm equivalence constant depending only on the resolution).
Concretely: a tempered distribution $f \in (B^{s_0}_{p, q_0}, B^{s_1}_{p, q_1})_{\theta, q}$ corresponds via $P$ to its Littlewood--Paley sequence $a = (\Delta_j f)_{j \ge 0}$, which lies in $(\ell^{q_0}_{s_0}(L^p), \ell^{q_1}_{s_1}(L^p))_{\theta, q} = \ell^q_{s_\theta}(L^p)$. The $\ell^q_{s_\theta}(L^p)$-norm of this sequence is, by definition, $\|f\|_{B^{s_\theta}_{p, q}}$. Conversely, $f \in B^{s_\theta}_{p, q}$ has Littlewood--Paley sequence in $\ell^q_{s_\theta}(L^p) = (\ell^{q_0}_{s_0}(L^p), \ell^{q_1}_{s_1}(L^p))_{\theta, q}$, and applying $S$ recovers $f$ in $(B^{s_0}_{p, q_0}, B^{s_1}_{p, q_1})_{\theta, q}$.
Hence
\begin{align*}
(B^{s_0}_{p, q_0}(\mathbb{R}^n), B^{s_1}_{p, q_1}(\mathbb{R}^n))_{\theta, q} = B^{s_\theta}_{p, q}(\mathbb{R}^n)
\end{align*}
with norms equivalent up to constants depending only on $n, s_0, s_1, p, q_0, q_1, q, \theta$, and the resolution of unity. This is the asserted identification.
[/step]