[step:Conclude that every Hörmander-admissible positive-degree cohomology class vanishes]Define $\operatorname{Dom}_{q,\varphi}(\bar\partial)$ to be the set of forms $a$ in the [weighted $L^2$ space](/page/Weighted%20L2%20Space) $L^2_{(0,q)}(\Omega,e^{-\varphi})$ whose [distributional](/page/Distribution) derivative $\bar\partial a$ belongs to $L^2_{(0,q+1)}(\Omega,e^{-\varphi})$. Define
\begin{align*}
Z^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)
&:= \{a \in \operatorname{Dom}_{q,\varphi}(\bar\partial) : \bar\partial a = 0 \text{ and } a \text{ satisfies the weighted hypotheses of the higher-degree Hörmander theorem}\},\\
B^{0,q}_{(2),\varphi}(\Omega)
&:= \{\bar\partial b : b \in \operatorname{Dom}_{q-1,\varphi}(\bar\partial)\}.
\end{align*}
The Hörmander-admissible weighted $L^2$ [Dolbeault cohomology](/page/Dolbeault%20Cohomology) group is the quotient [vector space](/page/Vector%20Space)
\begin{align*}
H^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)
:= Z^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)/B^{0,q}_{(2),\varphi}(\Omega),
\end{align*}
so two representatives define the same class exactly when their difference lies in $B^{0,q}_{(2),\varphi}(\Omega)$.
Let $[f] \in H^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)$ be a class with $1 \le q \le n$, represented by $f \in Z^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)$.
By the previous step, there exists such a form $u \in L^2_{(0,q-1)}(\Omega,e^{-\varphi})$ with $\bar\partial u = f$. Since $f \in L^2_{(0,q)}(\Omega,e^{-\varphi})$, this equality also shows that $u \in \operatorname{Dom}_{q-1,\varphi}(\bar\partial)$, so $f \in B^{0,q}_{(2),\varphi}(\Omega)$. Hence $f$ represents the zero class:
\begin{align*}
[f] = 0.
\end{align*}
Since $[f]$ was arbitrary, we obtain
\begin{align*}
H^{0,q}_{(2),\varphi,\mathrm{Hor}}(\Omega)=0
\end{align*}
for every $1 \le q \le n$.[/step]