[guided]The proof needs a division theorem with an estimate, not merely an algebraic assertion. We use the quantitative Skoda weighted $L^2$ division estimate as a previously established analytic result, specifically Théorème 1 of H. Skoda, "Application des techniques $L^2$ à la théorie des idéaux d'une algèbre de fonctions holomorphes avec poids", Annales scientifiques de l'École Normale Supérieure 5 (1972), 545-579. That result is stronger than the present statement because it gives an explicit weighted norm bound for the solution tuple.
Let $F:\Omega\to\mathbb C$ be the [holomorphic function](/page/Holomorphic%20Function) to which the estimate is applied. The estimate requires a pseudoconvex domain $\Omega\subset\mathbb C^n$, holomorphic functions $g_1,\dots,g_m\in\mathcal O(\Omega)$, the integer $q=\min\{n,m-1\}$, a real parameter $\alpha>1$, a plurisubharmonic function $\psi:\Omega\to[-\infty,\infty)$, and finiteness of
\begin{align*}
\int_\Omega |F|^2 |g|^{-2(\alpha q+1)}e^{-\psi}\,d\mathcal L^{2n}.
\end{align*}
We verify these inputs in the present theorem. The domain $\Omega$ is pseudoconvex by hypothesis. The functions $g_1,\dots,g_m$ and $f$ are holomorphic on $\Omega$ by hypothesis. The parameter satisfies $\alpha>1$ by hypothesis, the integer $q$ is exactly defined as $q=\min\{n,m-1\}$, and the weight $\psi$ is plurisubharmonic by hypothesis. Finally, the preceding step defined
\begin{align*}
I_f=\int_\Omega |f|^2 |g|^{-2(\alpha q+1)} e^{-\psi}\,d\mathcal L^{2n},
\end{align*}
and the theorem assumes $I_f<\infty$. Thus the quantitative Skoda estimate applies with $F=f$.
Applying the estimate with $F=f$ gives holomorphic functions $H_1,\dots,H_m\in\mathcal O(\Omega)$ satisfying
\begin{align*}
f=\sum_{j=1}^m g_jH_j
\end{align*}
and the quantitative bound
\begin{align*}
\int_\Omega |H|^2 |g|^{-2\alpha q}e^{-\psi}\,d\mathcal L^{2n}
\leq \frac{\alpha}{\alpha-1}
\int_\Omega |f|^2 |g|^{-2(\alpha q+1)}e^{-\psi}\,d\mathcal L^{2n},
\end{align*}
where $H:\Omega\to\mathbb C^m$ is the holomorphic map defined by $H(z)=(H_1(z),\dots,H_m(z))$. Since $\alpha>1$, we have
\begin{align*}
\frac{\alpha}{\alpha-1}<\infty.
\end{align*}
This is the point at which the strict inequality $\alpha>1$ is used quantitatively.[/guided]