[step:Translate maps out of $F(L)$ into cocones from $F \circ X$]For each object $d \in \mathcal D$, define $\operatorname{Cocone}_{\mathcal D}(F \circ X, d)$ to be the set of families
\begin{align*}
(\alpha_j: F(X(j)) \to d)_{j \in \mathcal J}
\end{align*}
such that for every morphism $u: j \to k$ in $\mathcal J$,
\begin{align*}
\alpha_k \circ F(X(u)) = \alpha_j.
\end{align*}
We prove that the function
\begin{align*}
\Phi_d: \operatorname{Hom}_{\mathcal D}(F(L), d) &\to \operatorname{Cocone}_{\mathcal D}(F \circ X, d) \\
\beta &\mapsto (\beta \circ F(\lambda_j))_{j \in \mathcal J}
\end{align*}
is a bijection.
Let
\begin{align*}
\theta_{c,d}: \operatorname{Hom}_{\mathcal D}(F(c), d) \to \operatorname{Hom}_{\mathcal C}(c, G(d))
\end{align*}
denote the adjunction bijection, natural in $c \in \mathcal C$ and $d \in \mathcal D$.
Given a cocone $(\alpha_j)_{j \in \mathcal J} \in \operatorname{Cocone}_{\mathcal D}(F \circ X, d)$, define morphisms
\begin{align*}
\widetilde{\alpha}_j := \theta_{X(j),d}(\alpha_j): X(j) \to G(d)
\end{align*}
in $\mathcal C$. For every morphism $u: j \to k$ in $\mathcal J$, naturality of $\theta$ in the $\mathcal C$-variable gives
\begin{align*}
\theta_{X(j),d}(\alpha_k \circ F(X(u)))
=
\theta_{X(k),d}(\alpha_k) \circ X(u).
\end{align*}
Since $(\alpha_j)$ is a cocone, $\alpha_k \circ F(X(u)) = \alpha_j$, hence
\begin{align*}
\widetilde{\alpha}_k \circ X(u) = \widetilde{\alpha}_j.
\end{align*}
Therefore $(\widetilde{\alpha}_j)_{j \in \mathcal J}$ is a cocone from $X$ to $G(d)$.
Because $(L, \lambda_j)$ is a colimit cocone, there exists a unique morphism
\begin{align*}
h: L \to G(d)
\end{align*}
such that
\begin{align*}
h \circ \lambda_j = \widetilde{\alpha}_j
\end{align*}
for every $j \in \mathcal J$. Define
\begin{align*}
\beta := \theta_{L,d}^{-1}(h): F(L) \to d.
\end{align*}
For each $j \in \mathcal J$, naturality of $\theta$ in the $\mathcal C$-variable gives
\begin{align*}
\theta_{X(j),d}(\beta \circ F(\lambda_j))
=
\theta_{L,d}(\beta) \circ \lambda_j
=
h \circ \lambda_j
=
\widetilde{\alpha}_j
=
\theta_{X(j),d}(\alpha_j).
\end{align*}
Since $\theta_{X(j),d}$ is a bijection, $\beta \circ F(\lambda_j) = \alpha_j$. Thus $\Phi_d(\beta) = (\alpha_j)_{j \in \mathcal J}$.
The same calculation shows uniqueness. If $\beta': F(L) \to d$ also satisfies $\beta' \circ F(\lambda_j) = \alpha_j$ for all $j$, then
\begin{align*}
\theta_{L,d}(\beta') \circ \lambda_j
=
\theta_{X(j),d}(\beta' \circ F(\lambda_j))
=
\theta_{X(j),d}(\alpha_j)
=
\widetilde{\alpha}_j
\end{align*}
for every $j$. By uniqueness in the colimit property of $L$, $\theta_{L,d}(\beta') = h$. Since $\theta_{L,d}$ is bijective, $\beta' = \beta$. Hence $\Phi_d$ is a bijection.[/step]