[step:Translate the Bergman condition into monomial-free initial circuit forms]Let $S_K := K[x_e : e \in E]$ be the [polynomial ring](/page/Polynomial%20Ring) with one variable for each element of $E$, and let $I(L) \subset S_K$ be the homogeneous linear ideal of polynomials vanishing on $L \subset K^E$. For a weight vector $w=(w_e)_{e \in E}\in\mathbb{R}^E$, choose a valued extension $F/K$ whose value group contains the subgroup of $\mathbb R$ generated by $v(K^\times)$ and the coordinates $w_e$, and let $v_F:F\to \mathbb R\cup\{\infty\}$ and $\kappa_F$ denote its valuation and residue field.
For a nonzero polynomial $f=\sum_u c_u x^u\in F[x_e:e\in E]$, where the sum is over a finite set of exponent vectors $u\in\mathbb N^E$, define the weight-minimum map
\begin{align*}
m_w: F[x_e:e\in E]\setminus\{0\}\to\mathbb R
\end{align*}
by
\begin{align*}
m_w(f):=\min_u(v_F(c_u)+w\cdot u).
\end{align*}
After choosing $\lambda\in F^\times$ with $v_F(\lambda)=-m_w(f)$, define the residue initial-form map up to nonzero scalar by
\begin{align*}
\operatorname{in}_w: F[x_e:e\in E]\setminus\{0\}\to \kappa_F[x_e:e\in E]/\kappa_F^\times
\end{align*}
where $\operatorname{in}_w(f)$ is represented by the reduction of the sum of the terms $\lambda c_u x^u$ for which $v_F(c_u)+w\cdot u=m_w(f)$. Replacing $\lambda$ by another element of the same valuation multiplies this representative by a nonzero scalar in $\kappa_F$, so the ideal generated by all such initial forms is independent of that rescaling. If one passes to a further valued extension, the residue-field initial ideal is obtained by scalar extension, so the property of containing a monomial is unchanged.
For a circuit $C$ with equation $f_C := \sum_{e \in C} a_e x_e \in I(L)$, where $a_e \in K_0^\times$, the $w$-initial form of $f_C$ is supported exactly on the set
\begin{align*}
C_{\min}(w) := \{e \in C : w_e = \min_{c \in C} w_c\}.
\end{align*}
Indeed, the coefficient valuations are all zero, so the terms of smallest weighted valuation in $f_C$ are precisely those indexed by $C_{\min}(w)$; reducing the coefficients cannot delete any of these terms because each $a_e$ has residue nonzero.
Assume now that $w \in \widetilde{\mathcal B}(M(L))$. Then $|C_{\min}(w)| \geq 2$ for every circuit $C$, so no initial circuit form $\operatorname{in}_w(f_C)$ is a monomial. For a linear form $g=\sum_{e\in E} b_e x_e$, define its support by $\operatorname{supp}(g):=\{e\in E:b_e\neq 0\}$.
Let $S_{K,1}$ denote the degree-one homogeneous part of $S_K$, and let $I(L)_1\subset S_{K,1}$ denote the $K$-[vector space](/page/Vector%20Space) of degree-one forms in $I(L)$. Define the degree-one residue initial space
\begin{align*}
W_w:=\operatorname{span}_{\kappa_F}\{\operatorname{in}_w(g):g\in I(L)_1\setminus\{0\}\}\subset \kappa_F[x_e:e\in E]_1.
\end{align*}
Here each $\operatorname{in}_w(g)$ is represented by any residue initial form of the nonzero linear form $g$, and the span is independent of the scalar choices.
[claim:Initial monomials in a linear ideal are detected by circuit forms]
Let $\mathcal C$ denote the set of circuits of $M(L)$. For every weight vector $w \in \mathbb{R}^E$, the valued initial ideal $\operatorname{in}_w(I(L))$ contains a monomial if and only if $\operatorname{in}_w(f_C)$ is a monomial for some circuit $C \in \mathcal C$.
[/claim]
[proof]
The space $W_w$ was defined above as the residue-field span of all initial forms of nonzero elements of $I(L)_1$. We first justify that $\operatorname{in}_w(I(L))$ is the linear ideal generated by $W_w$. Since $I(L)$ is generated by $I(L)_1$, every $f\in I(L)$ can be written as a finite sum $f=\sum_j q_j g_j$ with $g_j\in I(L)_1$ and $q_j\in K[x_e:e\in E]$. Taking residue initial forms gives $\operatorname{in}_w(f)$ in the ideal generated by the initial degree-one space after collecting all summands of minimal total weighted valuation; possible cancellation only replaces the displayed minimal linear combination by the initial form of another element of $I(L)_1$. Thus all initial forms of elements of $I(L)$ lie in $(W_w)$, while the reverse inclusion holds because each element of $W_w$ is an initial form of an element of $I(L)$. Hence
\begin{align*}
\operatorname{in}_w(I(L))=(W_w).
\end{align*}
A linear ideal generated by a vector subspace contains a monomial if and only if it contains a variable. Indeed, after a residue-field linear change of coordinates, the quotient by this linear ideal is a polynomial ring, hence no nonzero monomial is zero in the quotient unless one of its variable factors is zero in the quotient. Translating back, this means some variable belongs to the linear ideal, and because the ideal is generated in degree one, that variable lies in $W_w$.
A linear ideal generated by a vector subspace contains a monomial if and only if it contains a variable. Indeed, the quotient of a polynomial ring by a linear ideal is a polynomial ring over the residue field, hence an integral domain. If the class of a coordinate monomial is zero in this quotient, then the product of the classes of its coordinate factors is zero, so at least one coordinate variable has zero class and belongs to the linear ideal. Since the ideal is generated by the degree-one space $W_w$, that variable lies in $W_w$.
We now use the standard initial-circuit theorem for a represented valuated matroid. In the form needed here, let $D\subset K^E$ be a finite-dimensional vector space of linear dependences of a represented matroid, give each coordinate $e$ the real weight $w_e$, and let $\operatorname{in}_w(D)$ be the residue-field span of the initial forms of nonzero vectors of $D$. Then the nonzero inclusion-minimal supports in $\operatorname{in}_w(D)$ are exactly the circuits of the initial matroid; equivalently, they are the inclusion-minimal nonempty sets among $\operatorname{supp}(\operatorname{in}_w(d_C))$, where $C$ ranges over the circuits of the original represented matroid and $d_C\in D$ is any circuit vector supported on $C$. This is the represented case of valuated-circuit elimination: the circuit vectors of a representation satisfy valuated circuit elimination after weighting the coordinates, and their initial supports are precisely the circuits of the initial matroid.
We apply this theorem with $D=I(L)_1$, the dependence space of the coordinate functionals $(\ell_e)_{e\in E}$. The circuits of the original represented matroid are exactly the minimal supports of nonzero elements of $I(L)_1$, which are the circuits of $M(L)$. For such a circuit $C$, the earlier scalar-extension argument chooses a circuit vector $f_C=\sum_{e\in C}a_ex_e$ with every $a_e\in K_0^\times$, so all coefficient valuations are zero and $\operatorname{supp}(\operatorname{in}_w(f_C))=C_{\min}(w)$. Therefore the theorem identifies the nonzero inclusion-minimal supports in $W_w=\operatorname{in}_w(I(L)_1)$ with the minimal nonempty supports among these initial circuit forms.
If $\operatorname{in}_w(I(L))$ contains a monomial, then the preceding paragraph gives a variable $x_{e_0}\in W_w$. The singleton $\{e_0\}$ is then an inclusion-minimal nonzero support in $W_w$. By valuated-circuit elimination, there is a circuit $C$ of $M(L)$ such that $\operatorname{supp}(\operatorname{in}_w(f_C))=\{e_0\}$, so $\operatorname{in}_w(f_C)$ is a monomial. Conversely, if $\operatorname{in}_w(f_C)$ is a monomial for some circuit $C$, then it belongs to $\operatorname{in}_w(I(L))$, so the initial ideal contains a monomial.
[/proof]
By the claim, a monomial appears in $\operatorname{in}_w(I(L))$ if and only if the initial form of some circuit equation is a monomial. Since no circuit initial form is a monomial, $\operatorname{in}_w(I(L))$ contains no monomial.[/step]