J &:= \begin{pmatrix} f_u(u^*, v^*) & f_v(u^*, v^*) \\ g_u(u^*, v^*) & g_v(u^*, v^*) \end{pmatrix}, \quad D := \begin{pmatrix} D_1 & 0 \\ 0 & D_2 \end{pmatrix},
\end{align*}
where $f_u := \partial f/\partial u$, etc. Suppose the following four conditions hold:
(i) $\operatorname{tr}(J) < 0$.
(ii) $\det(J) > 0$.
(iii) $D_2\,J_{11} + D_1\,J_{22} > 0$, where $J_{11} := f_u(u^*, v^*)$ and $J_{22} := g_v(u^*, v^*)$.
(iv) $(D_2\,J_{11} + D_1\,J_{22})^2 > 4\,D_1\,D_2\,\det(J)$.
Then the steady state $(u^*, v^*)$ is linearly unstable to spatially inhomogeneous perturbations. More precisely, let $\mu$ be an eigenvalue of $-\Delta$ on $\Omega$ with homogeneous Neumann boundary conditions (i.e., $-\Delta\varphi = \mu\varphi$ in $\Omega$, $\partial_\nu\varphi = 0$ on $\partial\Omega$) with eigenfunction $\varphi$. If $\mu \in (k_-^2, k_+^2)$, then there exist $\lambda > 0$ and $\zeta \in \mathbb{R}^2 \setminus \{0\}$ such that $(U, V)^\top := \zeta\,e^{\lambda t}\,\varphi(x)$ solves the linearised system
\begin{align*}
\partial_t \begin{pmatrix} U \\ V \end{pmatrix} &= J \begin{pmatrix} U \\ V \end{pmatrix} + D\,\Delta \begin{pmatrix} U \\ V \end{pmatrix}.