[guided]The purpose of this step is to isolate the only effect of adding the stabilized variables $z$. Since the statement is microlocal near $C_{\phi_2}$, we first choose the phase-space neighbourhood and the amplitude representative so that the $z$-support lies in a small fixed neighbourhood of $0 \in \mathbb{R}^r$. On that neighbourhood, $z=0$ is the only stationary point of the $z$-phase; contributions from outside it are microlocally smoothing near $\lambda_0$ and cannot change the principal symbol.
For each fixed pair $(x,\eta)$, define the real quadratic map $q_{x,\eta}: \mathbb{R}^r \to \mathbb{R}$ by
\begin{align*}
q_{x,\eta}(z) := \frac{1}{2}\rho(x,\eta)z^\top H z.
\end{align*}
This is a genuine nonhomogeneous stationary phase problem in the variable $z$; the variables $(x,\eta)$ are parameters. The critical point is $z=0$, because the derivative with respect to $z$ is the [linear map](/page/Linear%20Map) represented by $\rho(x,\eta)Hz$, and this vanishes exactly at $z=0$ since $\rho(x,\eta)>0$ and $H$ is invertible.
The Hessian matrix at the critical point, meaning the Jacobian matrix of the gradient map $\nabla_z q_{x,\eta}:\mathbb{R}^r\to\mathbb{R}^r$ at $0$, is
\begin{align*}
\rho(x,\eta)H.
\end{align*}
The stationary phase theorem [citetheorem:8198] applies because this Hessian is invertible and the amplitude is classical in the homogeneous parameter $\eta$ while smooth with compactly localized support in the nonhomogeneous variable $z$. Multiplication by the positive scalar $\rho(x,\eta)$ does not change the numbers of positive and negative eigenvalues, so
\begin{align*}
\operatorname{sgn}(\rho(x,\eta)H)=\operatorname{sgn}(H).
\end{align*}
The determinant transforms by the elementary determinant identity for scalar multiplication of an $r \times r$ matrix:
\begin{align*}
\det(\rho(x,\eta)H)=\rho(x,\eta)^r\det H.
\end{align*}
Taking absolute values and the negative one-half power gives
\begin{align*}
|\det(\rho(x,\eta)H)|^{-1/2}=\rho(x,\eta)^{-r/2}|\det H|^{-1/2}.
\end{align*}
We also need the large parameter in stationary phase to be uniform on the conic neighbourhood. After shrinking that neighbourhood, write $\eta=\tau\omega$ with $\tau>0$ and $\omega$ in a compact subset of the unit sphere. Because $\rho$ is smooth, positive, and homogeneous of degree $1$, there are constants $0<c<C<\infty$ such that
\begin{align*}
c\tau \leq \rho(x,\tau\omega) \leq C\tau
\end{align*}
throughout the chosen neighbourhood. Hence $\rho(x,\eta)$ tends to infinity uniformly with $|\eta|$, which is exactly the large-parameter regime used in the stationary phase expansion.
The normalized stationary phase formula therefore says that the leading term produced by integration in $z$ is
\begin{align*}
e^{i\pi\operatorname{sgn}(H)/4}\rho(x,\eta)^{-r/2}|\det H|^{-1/2}a_{2,0}(x,\eta,0).
\end{align*}
This is exactly
\begin{align*}
F_H(x,\eta,0)a_{2,0}(x,\eta,0).
\end{align*}
The use of the total normalization $(2\pi)^{-(N_1+r)/2}$ is essential here: stationary phase in $r$ variables cancels precisely the additional factor $(2\pi)^{-r/2}$, so no extra power of $2\pi$ remains in $F_H$.
Finally, the next terms in stationary phase are obtained by applying differential operators in the $z$ variables and multiplying by negative powers of the large homogeneous scale. In this setting that scale is represented by the positive homogeneous function $\rho(x,\eta)$ of degree $1$ in $\eta$. Each subsequent term therefore has homogeneous degree at least one lower than the leading term. Hence those terms affect only lower conormal orders, while the principal conormal symbol receives exactly the factor $F_H$.[/guided]