[step:Show that the adjoint phase parametrizes the transposed canonical relation]
Define the adjoint phase $\psi: V \times U \times (\mathbb{R}^N \setminus \{0\}) \to \mathbb{R}$ by
\begin{align*}
\psi(y,x,\theta) = -\phi(x,y,\theta).
\end{align*}
Its critical set in the oscillation variables is
\begin{align*}
\Sigma_\psi = \{(y,x,\theta) : \partial_\theta \psi(y,x,\theta)=0\} = \{(y,x,\theta) : \partial_\theta \phi(x,y,\theta)=0\}.
\end{align*}
Thus the exchange map $\tau_\Sigma: \Sigma_\phi \to \Sigma_\psi$ defined by
\begin{align*}
\tau_\Sigma(x,y,\theta) = (y,x,\theta)
\end{align*}
is a diffeomorphism.
For $(x,y,\theta) \in \Sigma_\phi$, the canonical relation parametrized by $\psi$ is
\begin{align*}
(y,\partial_y\psi(y,x,\theta); x,-\partial_x\psi(y,x,\theta)) = (y,-\partial_y\phi(x,y,\theta); x,\partial_x\phi(x,y,\theta)).
\end{align*}
Since $\phi$ parametrizes
\begin{align*}
(x,\partial_x\phi(x,y,\theta); y,-\partial_y\phi(x,y,\theta)) \in C,
\end{align*}
the phase $\psi$ parametrizes
\begin{align*}
(y,-\partial_y\phi(x,y,\theta); x,\partial_x\phi(x,y,\theta)) \in C^t.
\end{align*}
Non-degeneracy is preserved because replacing $\phi$ by $-\phi$ and exchanging the base variables does not change the rank of the differentials defining the phase critical set. Hence the adjoint kernel is locally associated to $C^t$.
[/step]