[guided]We must check that the quotient constructed in one adapted chart is the same holomorphic vector bundle as the quotient constructed in another adapted chart. Let $U$ and $V$ be adapted coordinate neighbourhoods, with coordinates $z_1,\dots,z_n$ on $U$ and $w_1,\dots,w_n$ on $V$. On the overlap $U\cap V$, each $w_k$ is a [holomorphic function](/page/Holomorphic%20Function) of the $z$-coordinates:
\begin{align*}
w_k=w_k(z_1,\dots,z_n).
\end{align*}
The adapted condition says that $Y$ is cut out in the $w$-chart by
\begin{align*}
w_{r+1}=\cdots=w_n=0.
\end{align*}
Thus, for every normal index $\mu\in\{r+1,\dots,n\}$, the function $w_\mu$ vanishes identically on $Y\cap U\cap V$. If we differentiate this identity along a tangent coordinate direction $z_a$ with $a\in\{1,\dots,r\}$, we obtain
\begin{align*}
\left.\frac{\partial w_\mu}{\partial z_a}\right|_{Y\cap U\cap V}=0.
\end{align*}
This is the key block-triangularity statement: an adapted coordinate change cannot send a tangent direction of $Y$ into a normal direction to first order along $Y$.
Now apply the holomorphic chain rule to the ambient coordinate vector fields. For every normal $z$-direction $\nu\in\{r+1,\dots,n\}$, along $Y\cap U\cap V$ we have
\begin{align*}
\left.\frac{\partial}{\partial z_\nu}\right|_Y=\sum_{k=1}^{n}\left.\frac{\partial w_k}{\partial z_\nu}\right|_Y\left.\frac{\partial}{\partial w_k}\right|_Y.
\end{align*}
When we pass to the quotient by $T_Y$, every term involving $\partial/\partial w_k$ with $k\le r$ becomes zero, because these are precisely tangent vector fields to $Y$. Therefore the class of the $z_\nu$ normal vector is
\begin{align*}
q_U\left(\left.\frac{\partial}{\partial z_\nu}\right|_Y\right)=\sum_{\mu=r+1}^{n}\left.\frac{\partial w_\mu}{\partial z_\nu}\right|_Y q_V\left(\left.\frac{\partial}{\partial w_\mu}\right|_Y\right).
\end{align*}
The coefficients are holomorphic functions on $Y\cap U\cap V$ because the coordinate change is holomorphic.
It remains to justify invertibility of this transition matrix. The full Jacobian matrix
\begin{align*}
\left(\frac{\partial w_k}{\partial z_j}\right)_{k,j=1}^{n}
\end{align*}
is invertible because $z$ and $w$ are coordinate systems. The adapted condition gives $w_\mu|_Y=0$ for every $\mu\in\{r+1,\dots,n\}$, so differentiating along each tangent coordinate direction $z_a$ with $a\in\{1,\dots,r\}$ yields
\begin{align*}
\left.\frac{\partial w_\mu}{\partial z_a}\right|_Y=0.
\end{align*}
Hence the full Jacobian is block upper triangular along $Y$, with one diagonal block acting on tangent directions and the other diagonal block
\begin{align*}
\left(\left.\frac{\partial w_\mu}{\partial z_\nu}\right|_Y\right)_{\mu,\nu=r+1}^{n}
\end{align*}
acting on normal directions. Since an invertible block upper triangular matrix has invertible diagonal blocks, the normal block is invertible. Thus the quotient frames glue by holomorphic invertible transition functions, so they define a holomorphic vector bundle.[/guided]